• Tennis
• ITF Men - Singles
• M15 Bali 2
• Antoine Berger x Adhithya Ganesan Statistics

Antoine Berger vs Adhithya Ganesan statistics 17.09.2024

• 17/09/24 00:20
• 

  Antoine Berger
  • 0 : 2
  • Finished
  

  Adhithya Ganesan

T

1

2

Antoine Berger

0

3

2

Adhithya Ganesan

2

6

6

Antoine Berger

Stats

Adhithya Ganesan

• Match

Service

0/00%

First serve points %

0/00%

0/00%

Second serve points %

0/00%

0/00%

Break points %

0/00%

Return

0/00%

First return points %

0/00%

0/00%

Second return points %

0/00%

0/00%

Break points %

0/00%

Points

0/00%

Net points %

0/00%

0/00%

Service points %

0/00%

0/00%

Return points %

0/00%

0/00%

Total points %

0/00%

Games

0/00%

Service games %

0/00%

0/00%

Return games %

0/00%

0/00%

Total games %

0/00%

Antoine Berger

H2H

Adhithya Ganesan

All tournaments All matches

No matches

This is the first match of these players

Last results: Antoine Berger

ITF Men - Singles M15 La Paz 2

FT 27/11/25 12:00

Oliver Andre Solis Encinas

• 4
• 6
• 6

2 Antoine Berger

• 6
• 4
• 1

1

FT 26/11/25 13:00

Ezequiel Fagotti

• 6
• 2
• 4

1 Antoine Berger

• 3
• 6
• 6

2

ITF Men - Singles M25 Cochabamba 1

FT 19/11/25 18:20

Antoine Berger

• 6 ³
• 7 ⁷
• 6 ⁵

1 Tadeo Meneo

• 7 ⁷
• 6 ²
• 7 ⁷

2

ITF Men - Singles M25 Manzanillo 1

FT 12/11/25 11:20

Antoine Berger

• 6 ⁸
• 4

0 Segundo Goity Zapico

• 7 ¹⁰
• 6

2

ITF Men - Singles M25 Guadalajara 1

FT 04/11/25 16:15

Antoine Berger

• 3
• 3

0 Mauricio Schtulmann Gasca

• 6
• 6

2

Last results: Adhithya Ganesan

ITF Men - Singles M15 Kayseri 3 3

FT 05/06/26 03:00

Adhithya Ganesan

• 5
• 4

0 Dimitris Azoidis

• 7
• 6

2

FT 04/06/26 12:00

Adhithya Ganesan

• 6
• 6

2 Matas Vasiliauskas

• 4
• 3

0

FT 02/06/26 07:00

Adhithya Ganesan

• 6
• 6

2 Amir Milushev

• 0
• 1

0

Challenger Men - Singles Little Rock 1

FT 24/05/26 16:10

Johannus Monday

• 3
• 6
• 6

2 Adhithya Ganesan

• 6
• 3
• 4

1

ITF Men - Singles M25 Pensacola, FL 1

FT 16/05/26 11:00

Ryan Colby

• 6
• 6

2 Adhithya Ganesan

• 4
• 4

0