• Tennis
• Challenger Men - Singles
• Kobe (Japan), hard
• Yan Bai x Christoph Negritu Statistics

Yan Bai vs Christoph Negritu statistics 09.11.2024

• 09/11/24 21:10
• 

  Yan Bai
  • 2 : 1
  • Finished
  

  Christoph Negritu

T

1

2

3

Yan Bai

2

6

5

6

Christoph Negritu

1

4

7

4

Yan Bai

Stats

Christoph Negritu

• Match
• Set 1
• Set 2
• Set 3

Service

5

Aces

9

2

Double faults

2

62%

First serve percentage

64%

45/6668%

First serve points %

49/7268%

23/4156%

Second serve points %

19/4146%

6/967%

Break points %

14/1878%

Return

23/7232%

First return points %

21/6632%

22/4154%

Second return points %

18/4144%

4/1822%

Break points %

3/933%

Points

0/00%

Net points %

0/00%

68/10764%

Service points %

68/11360%

45/11340%

Return points %

39/10736%

113/22051%

Total points %

107/22049%

Games

13/1681%

Service games %

12/1675%

4/1625%

Return games %

3/1619%

17/3253%

Total games %

15/3247%

Yan Bai

H2H

Christoph Negritu

All tournaments All matches

No matches

This is the first match of these players

Last results: Yan Bai

Challenger Men - Singles Shanghai 1

FT 02/09/25 06:45

Yan Bai

• 3
• 0

0 Tsung-Hao Huang

• 6
• 6

2

ITF Men - Singles M15 Maanshan 5 1

Canc. 09/07/25 00:15

Yan Bai Aoran Wang

ITF Men - Singles M15 Maanshan 4 3

FT 03/07/25 23:30

Yan Bai

• 4
• 6
• 4

1 Yaojie Zeng

• 6
• 1
• 6

2

FT 03/07/25 02:45

Yan Bai

• 7
• 6

2 Aoran Wang

• 5
• 4

0

FT 01/07/25 23:40

Yan Bai

• 6
• 6

2 Wishaya Trongcharoenchaikul

• 4
• 1

0

Last results: Christoph Negritu

Challenger Men - Singles Heilbronn 1

FT 31/05/26 07:15

Max Wiskandt

• 7
• 6

2 Christoph Negritu

• 5
• 2

0

ITF Men - Singles M25 Troisdorf 1

Canc. 27/05/26 06:25

Christoph Negritu Kai Wehnelt

Challenger Men - Singles Madrid 1

Canc. 05/04/26 08:20

Pablo Manzano Lapuerta Christoph Negritu

Challenger Men - Singles Menorca 2

FT 01/04/26 06:10

Christoph Negritu

• 5
• 6 ²

0 Yaroslav Demin

• 7
• 7 ⁷

2

FT 30/03/26 08:05

Christoph Negritu

• 6
• 6

2 Juan Cruz Martin Manzano

• 4
• 4

0